determine the smallest 3 digit which is divisible by 6 8 and 12|Five digit numbers divisible by 12 : Tuguegarao Question. Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12. Solution. The least common multiple (LCM) of 2 or more numbers is the smallest . The 6/58 lotto result history and the Ultra Lotto summary for the Year 2022 are available on this website for everyone’s consumption. The 6/58 Ultra Lotto result is courtesy of the Philippine Charity Sweepstakes Office (PCSO). The game is conducted by PCSO from on Tuesday, Friday and Sunday at 9PM. 6/58 Lotto Result – History [.]
determine the smallest 3 digit which is divisible by 6 8 and 12,Thus, all the multiples of 24 will also be divisible by 6, 8, and 12. Now we will divide the smallest 3-digit number with the LCM obtained, and the remainder will be subtracted .Question. Determine the smallest 3 -digit number which is exactly divisible by 6, 8 and 12. Solution. Verified by Toppr. Smallest number exactly divisible by 6, 8 and 12. = .determine the smallest 3 digit which is divisible by 6 8 and 12Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12, is 120. You can also use the LCM Calculator to solve this.
Question. Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12. Solution. The least common multiple (LCM) of 2 or more numbers is the smallest .
The smallest 3-digit number which is exactly divisible by 6, 8, and 12 is 120. In Mathematics, the LCM is the value which is evenly divisible by the given two .
Hence, the smallest 3-digit number which is exactly divisible by 6, 8 and 12 is 120. This is the required answer. Note: In such types of questions it is always advisable .
Step-by-step explanation: Common Multiples of 6: 6,12,18,24,30,36,42. Common Multiples of 8: 8,16,24,32,40,48,54. Common Multiples of 12: .Question. Determine the smallest 3− digit number which is exactly divisible by 6,8 and 12. Solution. Verified by Toppr. Smallest number divisible by 6,8,12= L.C.M of 6,8,12. .determine the smallest 3 digit which is divisible by 6 8 and 12 Five digit numbers divisible by 12 The smallest 3-digit number divisible by 6, 8, and 12 is 24. Explanation: To determine the smallest 3-digit number that is exactly divisible by 6, 8, and 12, we need to . L.C.M. of 6, 8 and 12 = 2 x 2 x 2 x 3 = 24. The smallest 3-digit number = 100 . To find the number, we have to divide 100 by 24. Therefore, the required number = 100 .Now, 120 × 8 = 960 and 120 × 9 = 1080. We see that 120 × 9 = 1080 is a 4-digit number but, we need the greatest 3-digit multiple. Therefore, the greatest 3-digit multiple of 120 is 120 × 8 = 960 i.e, 960. Hence, the greatest 3-digit number exactly divisible by 8, 10, and 12 is 960. You can also use the LCM Calculator to solve this.so, l.c.m = 2 × 2 × 2 × 3 = 24 ∴ 24 is the smallest number divisible by 6 , 8 , 12 Now, we need to find the smallest 3 − digit number divisible by 6 , 8 , 12 report flag outlined. Answer: The required three digit number is 120 which exactly divisible by 6,8,12. Step-by-step explanation: To find : Determine the smallest 3-digit no. exactly divisible by 6,8,12 ? Solution : To get the number divisible by 6,8 and 12 we have to find the LCM of the numbers. 2 | 6 8 12.
Five digit numbers divisible by 12LCM of 6, 8 and 12 = 2×2×2×3 = 24. The smallest 3-digit number = 100. To find the smallest 3-digit number possible we have to look for smallest 3-digit multiples of 24. Multiples of 24 = 24, 48, 72, 96, 120, 144. Clearly, 120 is the smallest 3-digit multiple of 24. Therefore, the required number is 120.Answers (1) Smallest number = LCM of 6, 8, 12. We have to find the smallest 3-digit multiple of 24. It can be seen that. 24 4 = 96 and. 24 5 = 120. Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12 is 120. Posted by.Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12. Q. Find the smallest 6 digit number which is exactly divisible by 8, 15 and 18. Q. Find the smallest and the largest four-digit numbers which when lessened by 12 are exactly divisible by 16 , 24 a n d 40 . Question From - NCERT Maths Class 6 Chapter 3 EXERCISE 3.7 Question – 4 PLAYING WITH NUMBERS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-Determine .We have to find the greatest $$3$$-digit multiple of $$120$$. It can be seen that $$120\times 8=960$$ and $$120\times 9=1080$$. Hence, the greatest $$3$$-digit number exactly divisible by $$8, 10$$ and $$12$$ is $$960$$.
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